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47.7 Polynomial Division Verification

Polynomial Division Verification confirms accuracy by ensuring the divisor times quotient plus remainder equals the original dividend.

Polynomial Division Verification is the collection of checks used to confirm that a completed polynomial long division has been carried out correctly, examining the process at both the term level, as each step of the division cycle was performed, and the structural level, as the final quotient and remainder relate back to the original dividend and divisor. Because long division involves many repeated steps, each capable of introducing a small error, verification provides a systematic way to catch mistakes rather than relying solely on careful execution.

These checks range from confirming that no term of the dividend was overlooked to reconstructing the entire dividend from the final quotient and remainder, giving multiple independent opportunities to detect an error.


Confirming No Term Was Overlooked

Original Dividend Term Inventory

Before or during verification, every term of the original dividend, including any zero-coefficient placeholder terms inserted during preparation, is inventoried, so that each one can be accounted for as either contributing to the quotient or ending up in the final remainder.

Quotient Term Coverage Check

Each term of the quotient is checked to confirm it was generated from a genuine leading-term division step, one for each degree position from the dividend's degree down to the divisor's degree minus one, with no degree position skipped.

number of quotient terms = deg(dividend) deg(divisor) + 1

Checking the Mechanics of Each Pass

Partial Product Sign Check

Each partial product formed by multiplying the divisor by a quotient term is checked for sign consistency, confirming that a negative quotient term produced a partial product with correspondingly flipped signs across every term of the divisor.

Long-Division Subtraction Check

Each subtraction step is checked by confirming that the leading term of the partial product exactly cancels the leading term of the current working dividend, leaving a result whose degree has strictly decreased; a leading term that fails to cancel completely signals an arithmetic error in that pass.

leading term of current dividend leading term of partial product = 0

Checking the Final Output

Final Remainder Degree Check

The degree of the reported remainder is checked against the degree of the divisor, confirming that it is strictly less; a remainder whose degree is equal to or greater than the divisor's degree indicates that the division cycle was stopped prematurely, before it should have terminated.

Final Quotient Standard-Form Check

The quotient is checked to confirm it is arranged in standard form, with its terms ordered from highest degree to lowest degree, matching the conventional presentation expected of any completed polynomial expression.


Reconstructing the Dividend

Polynomial Division Reconstruction Check

The most comprehensive verification multiplies the divisor by the full quotient, then adds the remainder, and compares the result term by term against the original dividend; this single check simultaneously validates every step of the division cycle, since any error anywhere in the process would cause this reconstruction to fail.

dividend = (divisor·quotient) + remainder Reconstruction Check divisor · quotient + remainder = original dividend?

Exact-Division Product Check

When the remainder is zero, this check simplifies to confirming that the divisor multiplied by the quotient equals the dividend exactly, without any additional term needing to be added, providing a direct verification for exact division cases.

dividend = divisor · quotient

Worked Verification Example

Applying the Full Reconstruction

Given a division of 2x² + 5x − 1 by x + 2 producing quotient 2x + 1 and remainder −3, verification multiplies (x + 2)(2x + 1) to get 2x² + 5x + 2, then adds the remainder −3, giving 2x² + 5x − 1, which matches the original dividend exactly, confirming the division was performed correctly.

(x+2)(2x+1) +(3) = 2x2+5x1